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venkyelectrical
venkyelectrical
Asked: May 6, 2022In:

3. Consider the differential equation —da = f(x) where f has the graph shown. dr (a) 15 pc) Determine the equilibrium solutions. (b) [5 pt] Which solutions in (a) are stable and which are unstable? (c) [5 ptj Sketch the ...

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venkyelectrical
venkyelectrical
Asked: May 6, 2022In:

1 As a body body cools by radiation its temperature T at time k is a positive constant. t satisfies  the equation — dT = _ k 7- 4 where (a) (lOpt1 Find a general solution of the differential equation. ...

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venkyelectrical
venkyelectrical
Asked: May 6, 2022In:

4 in a wireless cellular system, let’s consider a cell with radius of 50Km” with /EIRP (Effective isotropic radiated Power) or 16w. The cos or blocking probability  “. is 3%. Assume that average call length (1/u) Is 10 minutes. and each user makes average of 6 calls/hour ( ).). Assume the cell has been allocated 8 MHz r spectral bandwidth with a full duplex channel bandwidth of 80 KHz (a) Calculate the traffic intensity ‘a’ per user Erlang (means user traffic intensity) (2)  (b) Decide the total number of channel ‘n’ per cell. (2) 4 \ bON we. : to 0 tic )cso (c) Decide the offered load Erlang using the result of (b) and GOS of 3%. [Use Erlang  B Table in Appendix A of the Text,_ 20.5.ESSI (2) \r) a-oe^ kct 0,0,111 go (d) Decide the Capacity of the Cell in terms of the Number of Users. (2) k o)”( I (01f we split the current cell of radius 50 Km into 5 Km- radius new cell, decide the new transmitted power Matt] for the split cell (assume propagation loss factor y =2). (1)

4 in a wireless cellular system, let’s consider a cell with radius of 50Km” with /EIRP (Effective isotropic radiated Power) or 16w. The cos or blocking probability  “. is 3%. Assume that average call length (1/u) Is 10 minutes. and ...

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venkyelectrical
venkyelectrical
Asked: May 6, 2022In:

3. This problem 1s on the free space path lose between a transmitter and a receiver separated by the distance d [Km]. Let’s assume that transmit power Pi- 20  antenna gain Gr. 10 db and Rx antenna gain G.- 20 Mt (a) Por the carrier frequency fe-2 GII7 and minimum required receiver sensitively of Po- – 40 dBm, find the maximum range of communication ‘d’ In km  (4) (b) Depending on the distance you found in part (a), If the answer in part (a) dots not guarantee the minimum communication range dmin= 6 Km, we hope to change the carrier frequency to other frequency. Decide whether we need to change G or not first. Then also decide whether the new frequency should be Iarper or smaller than G GI-17.. (4) (c) Assume that, in problem 3, the propagation path is modeled as 2-ray ground reflection (one LOS path and one ground reflected path) with the maximum distance you found in part (a), along with Tx antenna: Gt=10 dB with its height ht=30[m] , Rx antenna Gr=20 dB with its height hr=21m]. Calculate total path Loss using: (all log’ mean base ’10’, ‘d’ in imp PL[d13] = 40 log d –f Gt felBj+ Cr [dB) + 20 log ht + 20 log hrl. (4)

3. This problem 1s on the free space path lose between a transmitter and a receiver separated by the distance d [Km]. Let’s assume that transmit power Pi- 20  antenna gain Gr. 10 db and Rx antenna gain G.- 20 ...

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venkyelectrical
venkyelectrical
Asked: May 6, 2022In:

2. This problem is on the instantaneous Code and Huffman code. (n) For the 6- symbol source with probabilities 0.35, 0.25, 0.2, 0.1, 0.05 and 0.05, give Huffman Ternary Code and its Average  length.(show Table) (6) (b) Which of the following code(s) ...

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venkyelectrical
venkyelectrical
Asked: May 6, 2022In:

1. Assume that the received signal at the receiver antenna of the mobile is defined as r(0= 10 + 2 e Ham +3 efts) (a) Calculate the received signal envelope R CX24-Y2, where X denotes the real part and Y refers ...

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