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Home/microelectronics by sedra ad smith 8th edition chapter 9

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venkyelectrical
venkyelectrical
Asked: February 13, 2022In: microelectronics

9.83 In a particular BJT differential amplifier, a production error results in one of the transistors having an emitter–base junction area twice that of the other. With both inputs grounded, find the current in each of the two transistors and hence the dc offset voltage at the output, assuming that the collector resistances are equal. Use small-signal analysis to find the input voltage that would restore current balance to the differential pair. Repeat using large-signal analysis and compare results.

9.83 In a particular BJT differential amplifier, a production error results in one of the transistors having an emitter–base junction area twice that of the other. With both inputs grounded, find the current in each of the two transistors and ...

microelectronics by sedra ad smith 8th edition chapter 9
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venkyelectrical
venkyelectrical
Asked: February 13, 2022In: microelectronics

9.70 An NMOS differential pair is to be used in an amplifier whose drain resistors are 10 kΩ ± 1%. For the pair, imagesW/L = 4mA/V2. Decide whether to use a bias current I of 160 µA or 360 µA. Contrast the differential gain and input offset voltage for the two possibilities.

9.70 An NMOS differential pair is to be used in an amplifier whose drain resistors are 10 kΩ ± 1%. For the pair, imagesW/L = 4mA/V2. Decide whether to use a bias current I of 160 µA or 360 µA. ...

microelectronics by sedra ad smith 8th edition chapter 9
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venkyelectrical
venkyelectrical
Asked: February 12, 2022In: microelectronics

9.11 For the MOS differential pair in Fig. 9.5, specify the value of vid ≡ vG1 − vG2, in terms of VOV, that (a)causes iD1 to increase by 10% above its equilibrium value of I/2. (b)makes iD1/iD2 = 1.0; 2.0; 1.1; 1.01; 20. – 0.1VOV; (b) 0 V, 0.338VOV, 0.05VOV, 0.005VOV; 1.072VOV

9.11 For the MOS differential pair in Fig. 9.5, specify the value of vid ≡ vG1 − vG2, in terms of VOV, that (a)causes iD1 to increase by 10% above its equilibrium value of I/2. (b)makes iD1/iD2 = 1.0; 2.0; 1.1; 1.01; ...

microelectronics by sedra ad smith 8th edition chapter 9
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venkyelectrical
venkyelectrical
Asked: February 12, 2022In: microelectronics

9.16For a BJT differential amplifier utilizing transistors having β = 100, matched to 10% or better, and areas that are matched to 10% or better, along with collector resistors that are matched to 2% or better, find VOS, IB, and IOS. The dc bias current I is 100 µA. 2.55 mV; 0.5 µA; 50 nA

9.16For a BJT differential amplifier utilizing transistors having β = 100, matched to 10% or better, and areas that are matched to 10% or better, along with collector resistors that are matched to 2% or better, find VOS, IB, and ...

microelectronics by sedra ad smith 8th edition chapter 9
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Recent Comments

  1. venkyelectrical on Bonus Problem (10 points): In this circuit, the op amp is IDEAL. The op amp is NOT operating in the linear region. In this Circuit, V+=V_. The op amp output saturates at +12v. The output is always at saturation, either positive or negative. The output will “toggle” as Vin crosses a “threshold” voltage. Because of the positive feedback, the threshold voltage changes depending on the state of the output voltage. Find the lower and upper values of the threshold voltages to 5 places of precision.
  2. venkyelectrical on Problem #3 Operational Amplifiers (35 pts): The op amp is IDEAL and operating in the linear region. Find the voltage gain (Av) of the circuit. If Vin = -2, find io.
  3. venkyelectrical on Problem #2 Operational Amplifiers (35 pts): Op amp is ideal and operating in the linear region. Find the node voltages in the table.
  4. venkyelectrical on Problem #I Linear Amplifiers (40 pts) (SHOW ALL WORK) In the Problem, all resistor values are in ohms, voltages are volts and currents are amps. Amp “A” is voltage-to-current, Amps “B” and “C” are current-to-voltage. Use /1 = 0.01(V1), v2 = 100(/2) and V3 = 50(/3). Use Vin shown in the table. Find all the values listed in the table. Hint: Observe that R3, R4 and R5 are m parallel.
  5. venkyelectrical on 3. This problem is on the quantization and encoding. Answer to the following: Assume round-off rule for uniform quantization. We have 10 samples from the analog signal and their quantization error qε are found to be distributed as, qε =[0.33, 0.36, -0.38, 0.22, -0.4, 0.07, 0.4, -0.18, -0.25, 0.38] (a) Decide the suitable value of quantization step size ∆. Give reasoning for your answer (3) (b) We assume that qε are uniformly distributed with its probability density function f ∆ (∆) =1 /∆ for the interval [-∆/2, +∆/2]. Calculate the quantization noise power Pqε for the value of ∆ you found in part (a). (3) (c) Per the quantization noise power you calculated in part (b), calculate the signal power S [Watt] if output Signal to Q-zation noise power ratio SNRo = 30 dB. (3) (d) If we encode the quantizer output with binary code with length ‘n’(integer), decide the minimum code length ‘n’ based on the condition given in part (c) (1)

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