microelectronics by sedra and smith 8th edition chapter 10 Archives

Sign Up

Sign In

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Username* Please type your username.

E-Mail* Please type your E-Mail.

Question Title*

Please choose an appropriate title for the question so it can be answered easily.

Category* Please choose the appropriate section so the question can be searched easily.

Tags Please choose suitable Keywords Ex: question, poll.

Details*

Type the description thoroughly and in details.

Ask Anonymously

Captcha* Captcha Click on image to update the captcha.

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Ask A Question

venkyelectrical

Asked: February 23, 2022In: microelectronics

10.27A common-emitter amplifier has CC1 = CE = CC2 = 1µF, RB = 100 kΩ, Rsig = 5 kΩ, gm = 40 mA/V, rπ = 2.5 kΩ, RE = 5 kΩ, RC = 8 kΩ, and RL = 5 kΩ. Find the value of the time constant associated with each capacitor, and hence estimate the value of fL. Also compute the frequency of the transmission zero introduced by CE and comment on its effect on fL. τC1 = 7.44 ms; τCE = 0.071 ms; τC2 = 13 ms; fL = 2.28 kHz; fZ = 31.8 Hz, which is much smaller than fL and thus has a negligible effect on fL

10.27A common-emitter amplifier has CC1 = CE = CC2 = 1µF, RB = 100 kΩ, Rsig = 5 kΩ, gm = 40 mA/V, rπ = 2.5 kΩ, RE = 5 kΩ, RC = 8 kΩ, and RL = 5 kΩ. ...

venkyelectrical

Asked: February 23, 2022In: microelectronics

10.26A CS amplifier has CC1 = CS = CC2 = 1µF, RG = 10 MΩ, Rsig = 100 kΩ, gm = 2 mA/V, RD = RL = RS = 10 kΩ. Find AM, fP1, fP2, fP3, fZ, and fL. –9.9 V/V; 0.016 Hz; 334.2 Hz; 8 Hz; 15.91 Hz; 334.2 Hz

10.26A CS amplifier has CC1 = CS = CC2 = 1µF, RG = 10 MΩ, Rsig = 100 kΩ, gm = 2 mA/V, RD = RL = RS = 10 kΩ. Find AM, fP1, fP2, fP3, fZ, and fL. –9.9 V/V; ...

venkyelectrical

Asked: February 23, 2022In: microelectronics

10.25For the CC–CB amplifier of Fig. 10.34(a), let I = 0.5 mA, β = 100, Cπ = 6 pF, Cμ = 2 pF, Rsig = 10 kΩ, and RL = 10 kΩ. Find the low-frequency overall voltage gain AM, the frequencies of the poles, and the 3-dB frequency fH. Find fH both exactly and using the approximate formula in Eq. (10.150). 50 V/V; 6.4 MHz and 8 MHz; fH by exact evaluation = 4.6 MHz; fH using Eq. (10.150) = 5 MHz.

10.25For the CC–CB amplifier of Fig. 10.34(a), let I = 0.5 mA, β = 100, Cπ = 6 pF, Cμ = 2 pF, Rsig = 10 kΩ, and RL = 10 kΩ. Find the low-frequency overall voltage gain AM, the ...

venkyelectrical

Asked: February 23, 2022In: microelectronics

10.24Consider a CS amplifier having gm = 2 mA/V, ro = 20 kΩ, RL = 20 kΩ, Rsig = 20 kΩ, Cgs = 20 fF, Cgd = 5 fF, and CL = 5 fF. (a) Find the voltage gain AM and the 3-dB frequency fH (using the method of open-circuit time constants) and hence the gain–bandwidth product. (b) Repeat (a) for the case in which a resistance Rs is connected in series with the source terminal with a value selected so that gm Rs = 2. (a) –20 V/V, 61.2 MHz, 1.22 GHz; (b) –10 V/V, 109 MHz, 1.1 GHz

10.24Consider a CS amplifier having gm = 2 mA/V, ro = 20 kΩ, RL = 20 kΩ, Rsig = 20 kΩ, Cgs = 20 fF, Cgd = 5 fF, and CL = 5 fF. (a) Find the voltage gain AM ...

venkyelectrical

Asked: February 23, 2022In: microelectronics

10.23A bipolar current-mirror-loaded differential amplifier is biased with a current source I = 1 mA. The transistors are specified to have |VA| = 100 V. The total capacitance at the output node is 2 pF. Find the dc value, and the frequency of the dominant high-frequency pole, of the differential voltage gain. 2000 V/V; 0.8 MHz

10.23A bipolar current-mirror-loaded differential amplifier is biased with a current source I = 1 mA. The transistors are specified to have |VA| = 100 V. The total capacitance at the output node is 2 pF. Find the dc value, and ...

venkyelectrical

Asked: February 23, 2022In: microelectronics

10.22The differential amplifier specified in Exercise 10.21 has RSS = 75 kΩ and CSS = 0.4 pF. Find the 3-dB frequency of the CMRR. 5.3 MHz

venkyelectrical

Asked: February 23, 2022In: microelectronics

10.21A MOSFET differential amplifier such as that in Fig. 10.26(a) is biased with a current I = 0.8 mA. The transistors Q1 and Q2 have W/L = 100, images = 0.2 mA/V2, VA = 20 V, Cgs = 50 fF, Cgd = 10 fF, and Cdb = 10 fF. The drain resistors are 5 kΩ each. Also, there is a 100-fF capacitive load between each drain and ground. (a)Find VOV and gm for each transistor. (b)Find the differential gain Ad. (c)If the input signal source has a small resistance Rsig and thus the frequency response is determined primarily by the output pole, estimate the 3-dB frequency fH. [Hint: Refer to Section 10.2.3 and specifically to Eq. (10.45).] (d)If, in a different situation, the amplifier is fed symmetrically with a signal source of 20 kΩ resistance (i.e., 10 kΩ in series with each gate terminal), use the open-circuit time-constants method to estimate fH. [Hint: Refer to Section 10.3.3 and specifically to Eq. (10.68).] (a) 0.2 V, 4 mA/V; (b) 18.2 V/V; (c) 292 MHz; (d) 53.7 MHz

10.21A MOSFET differential amplifier such as that in Fig. 10.26(a) is biased with a current I = 0.8 mA. The transistors Q1 and Q2 have W/L = 100, images = 0.2 mA/V2, VA = 20 V, Cgs = 50 fF, ...

venkyelectrical

Asked: February 23, 2022In: microelectronics

10.20For an emitter follower biased at IC = 1 mA and having Rsig = RL = 1 kΩ, ro = 100 kΩ, β = 100, Cμ = 2 pF, CL = 0, and fT = 400 MHz, find the low-frequency gain AM, fZ, fP1, fP2, and an estimate for fH. 0.97 V/V; 458 MHz; 67.2 MHz; 562 MHz; 67.2 MHz

10.20For an emitter follower biased at IC = 1 mA and having Rsig = RL = 1 kΩ, ro = 100 kΩ, β = 100, Cμ = 2 pF, CL = 0, and fT = 400 MHz, find the low-frequency ...

venkyelectrical

Asked: February 17, 2022In: microelectronics

10.19In Example 10.8, even though we found that a dominant pole does not exist, use the method of open-circuit time constants to obtain an estimate for fH. (Hint: Recall that τH = b1.) fH = 1.53 GHz; about 18% lower than the exact value of 1.86 GHz; still not a bad estimate!

10.19In Example 10.8, even though we found that a dominant pole does not exist, use the method of open-circuit time constants to obtain an estimate for fH. (Hint: Recall that τH = b1.) fH = 1.53 GHz; about 18% lower than ...

venkyelectrical

Asked: February 17, 2022In: microelectronics

10.18Recalling that τH = b1, use the expression for b1 in Eq. (10.103) to find expressions for the three resistances Rgs, Rgd, and RCL for the source follower.

1 2 … 12

Sign Up

Sign In

Forgot Password

electricalstudent Latest Questions