11.25For the amplifier described in Exercise 11.24, rather than introducing a new dominant pole, we can use additional capacitance at the circuit node at which the first pole is formed to reduce the frequency of the first pole. If the ...

## electricalstudent Latest Questions

11.24A multipole amplifier having a first pole at 1 MHz and a dc open-loop gain of 100 dB is to be compensated for closed-loop gains as low as 20 dB by the introduction of a new dominant pole. At what ...

11.23For the amplifier whose open-loop-gain frequency response is shown in Fig. 11.38, find the value of β that results in a phase margin of 45°. What is the corresponding closed-loop gain? 10−4; 80 dB

11.22Find the closed-loop gain at ω1 relative to the low-frequency gain when the phase margin is 30°, 60°, and 90°. 1.93; 1; 0.707

11.21Consider an op amp having a single-pole, open-loop response with A0 = 105 and fP = 10 Hz. Let the op amp be ideal otherwise (infinite input impedance, zero output impedance, etc.). If this amplifier is connected in the noninverting ...

11.20Consider a feedback amplifier for which the open-loop transfer function A(s) is given by

11.19An amplifier with a low-frequency gain of 100 and poles at 104 rad/s and 106 rad/s is incorporated in a negative-feedback loop with feedback factor β. For what value of β do the poles of the closed-loop amplifier coincide? What ...

11.18An op amp having a single-pole rolloff at 100 Hz and a low-frequency gain of 105 is operated in a feedback loop with β = 0.01. What is the factor by which feedback shifts the pole? To what frequency? If ...

11.17If in the circuit in Fig. 11.30(a), R2 is short-circuited, find the ideal value of Af. For the case Rs = Rid = ∞, give expressions for Ri, Ro, A, β, Af, Rin, and Rout. Af = −1 A/A; Ri = ...

11.16For the amplifier in Example 11.10, find the values of Af, Rin, and Rout when the value of μ is 10 times lower, that is, when μ = 100. −9.91 A/A; 921 Ω; 101 MΩ