4.3.2. In this problem you are to decode the given line code sequences if there is no apparent
error in the sequence; if there is an error, decode as far as possible and then state the
nature of the error. If there is a first symbol in parentheses, do not decode it, but use it
to assist with decoding the remaining symbols.
(a) (+) – – + – – + + – + – + -, Bipolar NRZ-M.
(b) (+) – – + – – + + – + – + -, Bipolar NRZ-S.
(c) (+) – 0 0 + – + – 0 0 0 + -, NRZ-AMI.
(d) (+) 0 0 – + 0 – + 0 0 + 0 -, NRZ-AMI.
(e) -+ -+ +- +- +- +- -+ -+ -+ -+ +- -+, Biphase-L.
(f) -+ -+ — ++ — +- ++ -+ — ++ -+ -+, Biphase-M.
(g) -+ — ++ — +- +- ++ -+ +- ++ — ++, Biphase-S.
(h) +- — ++ — -+ +- — -+ +- — ++ +-, Delay modulation.
(i) ++ +- -+ ++ — ++ — -+ — ++ +- -+, Delay modulation.
(j) +- -+ ++ — — -+ +- -+ ++ — ++ +-, Delay modulation.
(k) + – 0 0 + 0 – + – 0 0 -, Dicode NRZ. (Assume data 0 before start of sequence.)
(l) + 0 – 0 0 0 0 + – + – 0, Dicode NRZ. (Assume data 0 before start of sequence.)
4.3.2. In this problem you are to decode the given line code sequences if there is no apparent error in the sequence; if there is an error, decode as far as possible and then state the nature of the error. If there is a first symbol in parentheses, do not decode it, but use it to assist with decoding the remaining symbols. (a) (+) – – + – – + + – + – + -, Bipolar NRZ-M. (b) (+) – – + – – + + – + – + -, Bipolar NRZ-S. (c) (+) – 0 0 + – + – 0 0 0 + -, NRZ-AMI. (d) (+) 0 0 – + 0 – + 0 0 + 0 -, NRZ-AMI. (e) -+ -+ +- +- +- +- -+ -+ -+ -+ +- -+, Biphase-L. (f) -+ -+ — ++ — +- ++ -+ — ++ -+ -+, Biphase-M. (g) -+ — ++ — +- +- ++ -+ +- ++ — ++, Biphase-S. (h) +- — ++ — -+ +- — -+ +- — ++ +-, Delay modulation. (i) ++ +- -+ ++ — ++ — -+ — ++ +- -+, Delay modulation. (j) +- -+ ++ — — -+ +- -+ ++ — ++ +-, Delay modulation. (k) + – 0 0 + 0 – + – 0 0 -, Dicode NRZ. (Assume data 0 before start of sequence.) (l) + 0 – 0 0 0 0 + – + – 0, Dicode NRZ. (Assume data 0 before start of sequence.)
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