A second-order control system has the closed-loop transfer function T(s)=Y(s)/R(s). The system specifications for a step input follow: (1) (15 pts) Percent overshoot P.O.≤5% (angle information is required) (2) (15 pts) Settling time Ts<4s (3) (15 pts) Peak time Tp<1s. Show the permissible area for the poles of T(s) corresponding to each of the desired response requirements. Use a 2% settling criterion to determine settling time.

A second-order control system has the closed-loop transfer function T(s)=Y(s)/R(s). The system specifications for a step input follow: (1) (15 pts) Percent overshoot P.O.≤5% (angle information is required) (2) (15 pts) Settling time Ts<4s (3) (15 pts) Peak time Tp<1s. Show the permissible area for the poles of T(s) corresponding to each of the desired response requirements. Use a 2% settling criterion to determine settling time.

59a7d032d27a145ac05b9626fddde271b57d0f97 138417932 - A second-order control system has the closed-loop transfer function T(s)=Y(s)/R(s). The system specifications for a step input follow: (1) (15 pts) Percent overshoot P.O.≤5% (angle information is required) (2) (15 pts) Settling time Ts&lt;4s (3) (15 pts) Peak time Tp&lt;1s. Show the permissible area for the poles of T(s) corresponding to each of the desired response requirements. Use a 2% settling criterion to determine settling time.A second-order control system has the closed-loop transfer function T(s)=Y(s)/R(s). The
system specifications for a step input follow:
(1) (15 pts) Percent overshoot P.O.≤5% (angle information is required)
(2) (15 pts) Settling time Ts<4s
(3) (15 pts) Peak time Tp<1s.
Show the permissible area for the poles of T(s) corresponding to each of the desired response
requirements. Use a 2% settling criterion to determine settling time.

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hwmadeeasy Selected answer as best October 15, 2021
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