D7.40 As we discussed in Section 7.3, there can be beneficial effects of having an unbypassed resistance Rs in the source lead of the CS amplifier. We can do this in the circuit of Fig. 7.57(a) by splitting the resistance RS into two resistances: Rs, which is left unbypassed, and (RS − Rs), across which the bypass capacitor CS is connected. Now, if, in order to improve linearity of the amplifier in Exercises 7.38 and 7.39, vgs is to be reduced to half its value, what value should Rs have? What would the amplifier gain Gv become? Recall that when Rs is included it becomes difficult to include ro in the analysis, so neglect it.
Rs = 500 Ω; Gv = −8.9 V/V