G(s)=1/(s+3)(s+6)(s+10) A-sketch root locus? B-design lag lead compensator, C(s),that cuts the peak time in half, maintains a 20% percent overshoot, and reduces the steady-state error of a step response four-fold (by 75% from uncompensated system ess). (determining the placement of any added poles or zeros and the new gain value K). C-Determine the compensation angle for the lead compensator component For the system shown in Figure I, where: G(s) (s + 3)(s + 6)(s + 10)
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